2X^2+3X=27 X=?
来源:百度知道 编辑:UC知道 时间:2024/06/20 02:38:00
2X^2+3X=27 X=?
5x^3-3x^2-32x-12 该怎么做啊 因式分解
5x^3-3x^2-32x-12 该怎么做啊 因式分解
2X^2+3X=27
2X^2+3X-27=0
(X-3)(2X+9)=0
X=3,X=-9/2
5x^3-3x^2-32x-12
=(5x^3-15x^2)+(12x^2-36x)+(4x-12)
=5x^2(x-3)+12x(x-3)+4(x-3)
=(x-3)(5x^2+12x+4)
=(x-3)(5x+2)(x+2)
1)原式可化为(x-3)(2x+9)=0 => x=3或x=-9/2
第一个等于3
(2x+9)(x—3)
2X^2+3X=27
2X²+3X-27=0
2X²-6X+9X-27=0
2X(X-3)+9(X-3)=0
(X-3)(2X+9)=0
X=3或X=-9/2
5x^3-3x^2-32x-12
=5x³+10x²-13x²-26x-6x-12
=5x²(x+2)-13x(x+2)-6(x+2)
=(x+2)(5x²-13x-6)
=(x+2)(5x²-15x+2x-6)
=(x+2)[(5x(x-3)+2(x-3)]
=(x+2)(5x+2)(x-3)
2X^2+3X=27
解:X^2+3X-27=0
(X-3)(2X+9)=0
X1=3,X2=-9/2
5x^3-3x^2-32x-12
=5(x^3+2x^2)-13(x^2+2x)-6(x+2)
=5x^2(x+2)-13x(x+2)-6(x+2)
=(x+2)(5x^2-13x-6)
=(x+2)(5x+2)(x-3)
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